K_ H value for some gases at the same temperature ' T ' are given: gas K_ H / k bar Ar 40.3 CO_2 1.67 HCHO 1.83 × 10^ -5 CH_4 0.413 where K_ H is Henry's Law constant in water. The order of their solubility in water is :

Correct answer: A. Ar CH_4>CO_2> Ar

NEET 2022

NEET 2022 · Chemistry · Solutions

K_ H value for some gases at the same temperature ' T ' are given:...

\mathrm{K}_{\mathrm{H}}

value for some gases at the same temperature '

\mathrm{T}

' are given:

<table class="qx-match-list qx-match-table" border="1" cellpadding="6" cellspacing="0"><tr><td>gas

K_{H} /

\mathbf{k}

barAr40.3CO_21.67HCHO1.83 \times 10^{-5}CH_40.413 where

\mathrm{K}_{

\mathrm{H}

}

is Henry's Law constant in water. The order of their solubility in water is :

A. $\mathrm{Ar} < \mathrm{CO}_2 < \mathrm{CH}_4 < \mathrm{HCHO}$

\mathrm{K}_{\mathrm{H}}=

Henry Law constant of gas in water, released to solubility as: Solubility of a gas

\propto \frac{1}{\mathrm{ K}_{\mathrm{H}} \text{ Value }}

This means higher is the value of

\mathrm{K}_{\mathrm{H}}

, lower will be the solubility of gas in water.

\therefore

Solubility order of given gas in water

=\mathrm{HCHO}>\mathrm{CH}_4>\mathrm{CO}_2>

\mathrm{Ar}