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NEET 2019
Exam
NEET
Year
2019
Subject
Chemistry
Chapter
Solutions

NEET 2019 · Chemistry · Solutions

In water saturated air the mole fraction of water vapour is 0.02 ....

In water saturated air the mole fraction of water vapour is 0.02 . If the total pressure of the saturated air is 1.2 atm1.2 \mathrm{~atm}, the partial pressure of dry air is

Options

  1. A1.18 atm1.18 \mathrm{~atm}
  2. B1.76 atm1.76 \mathrm{~atm}
  3. C1.176 atm1.176 \mathrm{~atm}
  4. D0.98 atm0.98 \mathrm{~atm}

Correct answer

C. 1.176 atm1.176 \mathrm{~atm}

Step-by-step solution

Partial pressure of dry air = total pressure ×\times mole fraction of dry air ⇒pdry air =ptotal ×λdry air  Given, λsaturated air =0.02λdry air =1−0.02=0.98ptotal =1.2atm∴pdry air =1.2atm×0.98=1.176atm\begin{array}{ll} \Rightarrow \quad \mathrm{p}_{\text{dry air }} & =\mathrm{p}_{\text{total }} \times \lambda_{\text{dry air }} \\ \text{ Given, } \lambda_{\text{saturated air }} & =0.02 \\ \lambda_{\text{dry air }} & =1-0.02=0.98 \\ \mathrm{p}_{\text{total }} & =1.2 \mathrm{ atm} \\ \therefore \quad \mathrm{p}_{\text{dry air }} & =1.2 \mathrm{ atm} \times 0.98=1.176 \mathrm{ atm} \end{array}
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