An excess of AgNO ₃ is added to 100 ~mL of a 0.01 M solution of dichlorotetraaquachromium (III) chloride. The number of moles of AgCl precipitate would be

Step-by-step solution

The formula of dichlorotetraqua chromium (III) chloride is [ Cr ( H ₂ O )₄ Cl ₂ ] Cl . On ionisation it generates only one Cl ⁻ ion. [ Cr ( H ₂ O )₄ Cl ₂ ] Cl [ Cr ( H ₂ O )₄ Cl ₂ ]⁺+ Cl ⁻ Initial 100 0.01 0 mmol =1 mmol After ionisation 0 1 mmol 1 mmol One mole of Cl ⁻ ions react with only 1 mole of AgNO ₃ molecule to produce 1 mole of AgCl . 1 mmol or 1 10⁻³ mole reacts with AgNO ₃ to give AgCl = 1 1 10⁻³ 1 =10⁻³ or 0.001 ~mol AgCl