NEET2012ChemistrySolutionsActual
p_A and p_B are the vapour pressure of pure liquid components, A and B , respectively of an ideal binary solution. If x_A represents the mole fraction of component A , the total pressure of the solution will be
Options
- Ap_A+x_A (p_B-p_A )
- Bp_A+x_A (p_A-p_B )
- Cp_B+x_A (p_B-p_A )
- Dp_B+x_A (p_A-p_B )
Correct answer
D. p_B+x_A (p_A-p_B )
Step-by-step solution
Total pressure, p_T=p_A^ +p_B^ We know that, p_A^ =p_A x_Ap_B^ =p_B x_B Substituting the values of p_A^ and p_B^ in Eq. (i) aligned p_T & =p_A x_A+p_B x_B [x_A+x_B . & .=1 x_A=1-x_B or x_B=1-x_A ] & =p_A x_A+p_B (1-x_A ) & =p_A x_A+p_B-p_B x_A p_T & =p_B+x_A (p_A-p_B ) aligned