NEET2010ChemistrySolutionsActual
A solution of sucrose (molar mass =342 ~g ~mol ⁻¹ ) has been prepared by dissolving 68.5 ~g of sucrose in 1000 ~g of water. The freezing point of the solution obtained will be ( k _ f . for water =1.86 ~K ~kg ~mol ⁻¹ )
Options
- A-0.372^ C
- B-0.520^ C
- C+0.372^ C
- D-0.570^ C
Correct answer
A. -0.372^ C
Step-by-step solution
Depression in freezing point, aligned & T _ f = k _ f m & where, aligned & m = molality = w _ B 1000 M _ B W _ A &= 68.5 1000 342 1000 = 68.5 342 & T _ f =1.86 68.5 342 &= 0.372^ C & T _ f = T ^0- T _s &= 0-0.372^ C &=-0.372^ C aligned aligned