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NEET 2006
Exam
NEET
Year
2006
Subject
Chemistry
Chapter
Solutions

NEET 2006 · Chemistry · Solutions

1.00 ~g of non-eletrolyte solute (molar mass 250 ~g ~mol^ -1 ) was...

1.00 g1.00 \mathrm{~g} of non-eletrolyte solute (molar mass 250 g mol−1250 \mathrm{~g} \mathrm{~mol}^{-1} ) was dissolved in 51.2 g51.2 \mathrm{~g} of benzene. If the freezing point depression constant, Kf\mathrm{K}_f of benzene is 5.12 Kkgmol−1\mathrm{K} \mathrm{kg} \mathrm{mol}^{-1}, the freezing point of benzene will be lowered by:

Options

  1. A0.2 K0.2 \mathrm{~K}
  2. B0.4 K0.4 \mathrm{~K}
  3. C0.3 K0.3 \mathrm{~K}
  4. D0.5 K0.5 \mathrm{~K}

Correct answer

B. 0.4 K0.4 \mathrm{~K}

Step-by-step solution

Molality of a non-electrolyte solute  weight of solute in gram  molecular weight of solute  weight of solvent in kg =12500.0512=1250×0.0512=0.0781 mΔTf=kf× molality of solution =5.12×0.0781=0.4 K\begin{aligned}& \frac{\frac{\text{ weight of solute in gram }}{\text{ molecular weight of solute }}}{\text{ weight of solvent in kg }}\\ & =\frac{\frac{1}{250}}{0.0512}=\frac{1}{250 \times 0.0512}\\ & =0.0781 \mathrm{~m}\\ \Delta \mathrm{T}_f & =k_f \times \text{ molality of solution }\\ & =5.12 \times0.0781=0.4 \mathrm{~K} \end{aligned}
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