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NEET 2005
Exam
NEET
Year
2005
Subject
Chemistry
Chapter
Solutions

NEET 2005 · Chemistry · Solutions

The vapour pressure of two liquids P and Q are 80 and 60 torr...

The vapour pressure of two liquids PP and Q\mathrm{Q} are 80 and 60 torr respectively. The total vapour pressure of solution obtained by mixing 3 mole of P\mathrm{P} and 2 mol2 \mathrm{~mol} of Q\mathrm{Q} would be:

Options

  1. A72 torr
  2. B140 torr
  3. C68 torr
  4. D20 torr

Correct answer

A. 72 torr

Step-by-step solution

By Raoult's Law PT=PP∘XP+PQ∘XQ\mathrm{P}_{\mathrm{T}}=\mathrm{P}_{\mathrm{P}}^{\circ} \mathrm{X}_{\mathrm{P}}+\mathrm{P}_{\mathrm{Q}}^{\circ} \mathrm{X}_{\mathrm{Q}} PP∘=80 torr XP=35PQ∘=60 torr \begin{aligned} & \mathrm{P}_{\mathrm{P}}^{\circ}=80 \text{ torr } \\ & \mathrm{X}_{\mathrm{P}}=\frac{3}{5} \\ & \mathrm{P}_{\mathrm{Q}}^{\circ}=60 \text{ torr } \end{aligned} XQ=25PT=80×35+60×25=48+24PT=72 torr. \begin{aligned} \mathrm{X}_{\mathrm{Q}} & =\frac{2}{5} \\ \mathrm{P}_{\mathrm{T}} & =80 \times \frac{3}{5}+60 \times \frac{2}{5} \\ & =48+24 \\ \mathrm{P}_{\mathrm{T}} & =72 \text{ torr. } \end{aligned} Related Theory Solutes which dissociate or associate in a particular solution will not obey Raoult's law. Raoult's law applies to solutions containing non-volatile solute only. Raoult's law cannot be applied to concentrated solutions.
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