A vessel contains 3.2 ~g of dioxygen gas at STP (273.15 K and 1 atm pressure). The gas is now transferred to another vessel at constant temperature, where pressure becomes one third of the original pressure. The volume of new vessel in L is : (Given - molar volume at STP is 22.4 ~L )

Step-by-step solution

No. of moles of O ₂= Given weight of O ₂ Mol. weight of O ₂ = 3.2 32 =0.1 Molar vol. at STP =0.1 22.4=2.24 ~L P ₁=1 ~atm , ~V ₁=2.24 ~L , P ₂= 1 3 ~atm , ~V ₂= ? According to Boyle's law : P ₁ ~V ₁= P ₂ ~V ₂ aligned 1 2.24 & = 1 3 V ₂ ~V ₂ & =2.24 3 & =6.72 ~L aligned