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NEET2020ChemistryStates of MatterActual

The minimum pressure required to compress 600   dm 3 of a gas at 1 bar to 150   dm 3 at 40 ° C is

Options

  1. A4 . 0   bar
  2. B0 . 2   bar
  3. C1 . 0   bar
  4. D2 . 5   bar

Correct answer

A. 4 . 0   bar

Step-by-step solution

By Boyle's law P 1 V 1 = P 2 V 2 1   bar × 600 dm 3 = P 2 × 150 dm 3 P 2 = 4

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