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NEET 2017
Exam
NEET
Year
2017
Subject
Chemistry
Chapter
States of Matter

NEET 2017 · Chemistry · States of Matter

A 20litre container at 400K contains CO _ 2 (g) at pressure 0 ....

A 20litre20litre container at400K400K contains CO2(g){CO}_{2}\left(g\right) at pressure 0.4atm0 . 4atm and an excess of SrOSrO (neglect the volume of solid SrOSrO ). The volume of the container is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when the pressure of CO2{CO}_{2} attains its maximum value, will be:

\left(Giventhat: {SrCO}_{3}\left(s\right) ⇌ SrO\left(s\right) + {CO}_{2}\left(g\right), {K}_{p} = 1 .6 atm\right)

Options

  1. A5litre5litre
  2. B10litre10litre
  3. C4litre4litre
  4. D2litre2litre

Correct answer

A. 5litre5litre

Step-by-step solution

Max. pressure of CO2={CO}_{2} =Pressure of CO2{CO}_{2} at equilibrium.

For reaction,

SrCO3(s)⇌SrO(s)+CO2{SrCO}_{3}\left(s\right) ⇌ SrO\left(s\right) + {CO}_{2}

Kp=PCO2=1.6{K}_{p} = {P}_{{CO}_{2}} = 1 .6 atm = maximum pressure of CO2{CO}_{2}.

The volume of the container at this stage.

V=nRTPV = \dfrac{nRT}{P} ......(i)

Since the container is sealed and the reaction was not earlier at equilibrium

∴n∴ n=constant

n=PVRT=0.4×20RTn = \dfrac{PV}{RT} = \dfrac{0 .4 \times 20}{RT} ......(ii)

Put equation (ii) in equation (i)

V=[0.4×20RT]RT1.6=5LV = \left[\dfrac{0 .4 \times 20}{RT}\right]\dfrac{RT}{1 .6} = 5L
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