50 ~mL of each gas A and of gas B takes 150 and 200 ~s respectively for effusing through a pin hole under the similar conditions. If molecular mass of gas B is 36 , the molecular mass of gas A will be

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Correct answer: D. 20.25

Given, aligned V_A & =V_B=50 mL T_A & =150 s T_B & =200 s M_B & =36 M_A & =? aligned From Graham's law of effusion aligned (r_B)/(r_A) & = (M_A)/(M_B) =(V_B T_A)/(T_B · V_A) (M_A)/(36) & =(V_A × 150)/(200 × V_A) or (M_A)/(36) & =(15)/(20)=(3)/(4) (M_A)/(36) & =(9)/(16) M_A & =(9 × 36)/(16)=(9 × 9)/(4)=(81)/(4)=20.25 aligned

50 ~mL of each gas A and of gas B takes 150 and 200 ~s respectively...

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