NEET2012ChemistryStates of MatterActual
50 ~mL of each gas A and of gas B takes 150 and 200 ~s respectively for effusing through a pin hole under the similar conditions. If molecular mass of gas B is 36 , the molecular mass of gas A will be
Options
- A96
- B128
- C32
- D20.25
Correct answer
D. 20.25
Step-by-step solution
Given, aligned V_A & =V_B=50 ~mL T_A & =150 ~s T_B & =200 ~s M_B & =36 M_A & =? aligned From Graham's law of effusion aligned r_B r_A & = M_A M_B = V_B T_A T_B V_A M_A 36 & = V_A 150 200 V_A or M_A 36 & = 15 20 = 3 4 M_A 36 & = 9 16 M_A & = 9 36 16 = 9 9 4 = 81 4 =20.25 aligned