The volume occupied by 1.8 ~g of water vapour at 374^ C and 1 bar pressure will be [Use R =0.083 bar L K ⁻¹ ~mol ⁻¹ ]

Step-by-step solution

According to ideal gas equation, aligned & pV = nRT & V = nRT p = w M.wt RT p ( i ) [ n = w M wt ] aligned Given, w =1.8 ~g , ~T =374^ C =(374+273) K =647 ~K p =1 bar, R =0.083 bar LK ⁻¹ ~mol ⁻¹ On substituting the given values in Eq. (i), we get aligned V & = 1.8 ~g 18 ~g ~mol ⁻¹ 0.083 bar LK ⁻¹ ~mol ⁻¹ 647 ~K 1 bar & =5.37 ~L aligned