NEET2010ChemistryStates of MatterActual
The pressure exerted by 6.0 ~g of methane gas in a 0.03 ~m ^3 vessel at 129^ C is (Atomic masses : C =12.01, H =1.01 and R =8.314 JK ⁻¹ ~mol ⁻¹ )
Options
- A215216 ~Pa
- B13409 ~Pa
- C41648 ~Pa
- D31684 ~Pa
Correct answer
C. 41648 ~Pa
Step-by-step solution
Given, volume, V =0.03 ~m ^3 temperature, T =129+273=402 ~K mass of methane, w=6.0 ~g mol. mass of methane, M=12.01+4 1.01=16.05 From, ideal gas equation, aligned & pV = nRT & p = 6 16.05 8.314 402 0.03 =41648 ~Pa aligned