Given below are two statements: Statement I: The Balmer spectral line for H atom with lowest energy is locateld at (5)/(36) R_H ~cm^ -1 . (R_ H =. Rydberg constant ) Statement II: When the temperature of blackbody

Correct answer: C. Both Statement I and Statement II are true For Balmer series n_1=2 n_2=3 v =(1)/(λ)=R_H[(1)/(n_1^2)-(1)/(n_2^2)] v =R_H[(1)/(4)-(1)/(9)] v =(5 R_H)/(36) ~cm^ -1

NEET 2024

Exam: NEET
Year: 2024
Subject: Chemistry
Chapter: Structure of Atom

NEET 2024 · Chemistry · Structure of Atom

Given below are two statements: Statement I: The Balmer spectral...

Given below are two statements: Statement I: The Balmer spectral line for

H

atom with lowest energy is locateld at

\frac{5}{36} R_H \mathrm{~cm}^{-1}

\left(\mathrm{R}_{\mathrm{H}}=\right.

Rydberg constant ) Statement II: When the temperature of blackbody increases, the maxima of the curve (intensity and wavelength) shifts to shorter wavelength. In the light of the above statements, choose the correct answer from the options given below: Given below are two statements: Statement I: The Balmer spectral line for H atom with lowest energy is locateld at

Given below are two statements: Statement I: The Balmer spectral line for H atom with lowest energy is locateld at

Options

AStatement I is true but Statement II is false
BStatement I is false but Statement II is true
CBoth Statement I and Statement II are true
DBoth Statement I and Statement II are false

Correct answer

C. Both Statement I and Statement II are true

Step-by-step solution

For Balmer series

\mathrm{n}_1=2

\mathrm{n}_2=3

\bar{v}=\frac{1}{\lambda}=R_H\left[\frac{1}{n_1^2}-\frac{1}{n_2^2}\right]

\bar{v}=R_H\left[\frac{1}{4}-\frac{1}{9}\right]

\bar{v}=\frac{5 R_H}{36} \mathrm{~cm}^{-1}

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