The work done during reversible isothermal expansion of one mole of hydrogen gas at 25^ C from pressure of 20 atmosphere to 10 atmosphere is (Given R=2.0 cal K^ -1 ~mol^ -1 )

Correct answer: A. -413.14 calories aligned W_ rev, iso & =-2.303 n R T (P_i)/(P_f) & =-2.303 × 1 × 2 × 298 × 2 & =-2.303 × 1 × 2 × 298 × 0.3 & =-413.14 calories aligned

NEET 2024

Exam: NEET
Year: 2024
Subject: Chemistry
Chapter: Thermodynamics (C)

NEET 2024 · Chemistry · Thermodynamics (C)

The work done during reversible isothermal expansion of one mole of...

The work done during reversible isothermal expansion of one mole of hydrogen gas at

25^{\circ} \mathrm{C}

from pressure of 20 atmosphere to 10 atmosphere is (Given

\mathrm{R}=2.0 \mathrm{cal} \mathrm{K}^{-1} \mathrm{~mol}^{-1}

)

Options

A-413.14 calories
B413.14 calories
C100 calories
D0 calorie

Correct answer

A. -413.14 calories

Step-by-step solution

\begin{aligned} W_{\text{rev, iso }} & =-2.303 n R T \log \frac{P_i}{P_f} \\ & =-2.303 \times 1 \times 2 \times 298 \times \log 2 \\ & =-2.303 \times 1 \times 2 \times 298 \times 0.3 \\ & =-413.14 \text{ calories }\end{aligned}

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