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NEET 2023
Exam
NEET
Year
2023
Subject
Chemistry
Chapter
Thermodynamics (C)

NEET 2023 · Chemistry · Thermodynamics (C)

The equilibrium concentrations of the species in the reaction A + B...

The equilibrium concentrations of the species in the reaction A+B⇋C+DA + B ⇋ C + D are 2,3,10and6molL−12, 3, 10and6mol{L}^{- 1} respectively at 300K300K. ∆G∘∆ {G}^{∘} for the reaction is

\left(R = 2cal / molK\right)$

Options

  1. A−13.73cal- 13 . 73cal
  2. B−1372.60cal- 1372 . 60cal
  3. C−137.26cal- 137 . 26cal
  4. D−1381.80cal- 1381 . 80cal

Correct answer

D. −1381.80cal- 1381 . 80cal

Step-by-step solution

A+B⇔C+Datequilibrium23106A + B ⇔ C + Datequilibrium23106

Keq=[C][D][A][B]Keq=10×62×3=10∆Gº=–RTlnK{K}_{eq} = \dfrac{[ C ] [ D ]}{[ A ] [ B ]}{K}_{eq} = \dfrac{10 \times 6}{2 \times 3} = 10 ∆ G º = – RTlnK

Where RR is the gas constant,TTis the temperature in Kelvin, and KK is the equilibrium constant of the reaction.

ΔG=−2.303×2×300×log⁡1010=−2.303×2×300×1=−1381.8cal\Delta G = - 2 . 303 \times 2 \times 300 \times \log_{10}10 = - 2 . 303 \times 2 \times 300 \times 1 = - 1381 . 8cal

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