The bond dissociation energies of X _ 2 Y _ 2 and XY are in the ratio of 1: 0 .5 : 1 . Δ H for the formation of XY is - 200kJ mol ^ - 1 . What will be the bond dissociation energy of X _ 2 ?

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Correct answer: A. 800kJ mol ^ - 1

Let B.E. of x _ 2 , y _ 2 and xy are xkJ mol ^ - 1 , 0 .5 xkJ mol ^ - 1 and xkJ mol ^ - 1 respectively (1)/(2) X _ 2 + (1)/(2) Y _ 2 → XY; Δ H = - 200kJ mol ^ - 1 Δ H = - 200 = Σ (B . E) _ Reactant - Σ (B . E) _ Product - 200 = [(1)/(2) × (x) + (1)/(2) × (0 .5 x)] - [1 × (x)] ⇒ x = 800kJmol B.E of X _ 2 = 800kJ mol ^ - 1

The bond dissociation energies of X _ 2 Y _ 2 and XY are in the...

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