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NEET 2015
Exam
NEET
Year
2015
Subject
Chemistry
Chapter
Thermodynamics (C)

NEET 2015 · Chemistry · Thermodynamics (C)

The heat of combustion of carbon to C O _ 2 is - 393 . 5kJ / mol ....

The heat of combustion of carbon to CO2C{O}_{2} is−393.5kJ/mol- 393 . 5kJ / mol. The heat released upon the formation of 35.2g35 . 2g of CO2C{O}_{2} from carbon and oxygen gas is

Options

  1. A−315kJ- 315kJ
  2. B+315kJ+ 315kJ
  3. C−630kJ- 630kJ
  4. D−3.15kJ- 3.15kJ

Correct answer

A. −315kJ- 315kJ

Step-by-step solution

Formation of CO2C{O}_{2} from carbon and dioxygen gas can be represented as

C(s)+O2(g)→CO2(g);∆fH=−393.5kJmol−1C\left(s\right) + {O}_{2 ( g )} \to C{O}_{2 ( g )}; {∆}_{f}H = - 393.5kJmo{l}^{- 1}

(1mole=44g1mole = 44g)

The heat released on formation of 44g44g CO2C{O}_{2}

=−393.5kJmol−1= - 393.5kJmo{l}^{- 1}

=−393.5kJmol−144g×35.2g= \dfrac{- 393.5kJmo{l}^{- 1}}{44g} \times 35.2g

=−315kJ= - 315kJ
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