Standard entropies of X ₂, Y ₂ and XY ₃ are 60,40 and 50 ~J ~K ~K ⁻¹ ~mol ⁻¹ respectively. For the reaction 1 2 X ₂+ 3 2 Y ₂ XY ₃ ; H =-30 ~kJ , to be at equilibrium, the temperature should be

Step-by-step solution

For the reaction, aligned & 1 2 X ₂+ 3 2 Y ₂ XY ₃ ; H =-30 ~kJ & S ^ = S _ ( XY ₃ ) ^ - [ 1 2 ~S _ X ₂ ^ + 3 2 ~S _ Y ₂ ^ ] & =50- [ 1 2 60+ 3 2 40 ] & =50-[30+60]=50-90 & =-40 JK ⁻¹ ~mol ⁻¹ aligned We know that, G ^ = H ^ - T S ^ At equilibrium, aligned G ^ & =0 H & = T S ^ T & = H S ^ = -30 10^3 ~J -40 ~J ~K ⁻¹ ~mol ⁻¹ =750 ~K aligned