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NEET 2020
Exam
NEET
Year
2020
Subject
Chemistry
Chapter
Thermodynamics (C)

NEET 2020 · Chemistry · Thermodynamics (C)

Hydrolysis of sucrose is given by the following reaction. Sucrose +...

Hydrolysis of sucrose is given by the following reaction.
Sucrose +H2O⇌+ {H}_{2}O ⇌ Glucose ++ Fructose
If the equilibrium constant (KC)\left({K}_{C}\right) is 2×10132 \times {10}^{13} at 300K300K, the value of ΔrG⊖{\Delta}_{r}{G}^{⊖} at the same temperature will be:

Options

  1. A8.314Jmol–1K–1×300K×ln⁡(2×1013)8.314J{mol}^{– 1}{K}^{– 1} \times 300K \times \ln \left(2 \times {10}^{13}\right)
  2. B8.314Jmol–1K–1×300K×ln⁡(3×1013)8.314J{mol}^{– 1}{K}^{– 1} \times 300K \times \ln \left(3 \times {10}^{13}\right)
  3. C–8.314Jmol–1K–1×300K×ln⁡(4×1013)– 8.314J{mol}^{– 1}{K}^{– 1} \times 300K \times \ln \left(4 \times {10}^{13}\right)
  4. D–8.314Jmol–1K–1×300K×ln⁡(2×1013)– 8.314J{mol}^{– 1}{K}^{– 1} \times 300K \times \ln \left(2 \times {10}^{13}\right)

Correct answer

D. –8.314Jmol–1K–1×300K×ln⁡(2×1013)– 8.314J{mol}^{– 1}{K}^{– 1} \times 300K \times \ln \left(2 \times {10}^{13}\right)

Step-by-step solution

Kc=2×1013{K}_{c} = 2 \times {10}^{13}

T=300KT = 300K

ΔGo=−RTlnkeq{\Delta G}^{o} = - RT{lnk}_{eq}

ΔGo=−8.314JK−1mol−1×300K×ln⁡(2×1013){\Delta G}^{o} = - 8 . 314{JK}^{- 1}{mol}^{- 1} \times 300K \times \ln \left(2 \times {10}^{13}\right)

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