From the following bond energies : H - H bond energy : 431.37 ~kJ ~mol ⁻¹ C = C bond energy : 606.10 ~kJ ~mol ⁻¹ C - C bond energy : 336.49 ~kJ ~mol ⁻¹ C - H bond energy : 410.50 ~kJ ~mol ⁻¹ Enthalpy for the reaction, will be :

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Correct answer: D. -120.0 ~kJ ~mol ⁻¹

H = dissociation energy of reactant - Bond dissociation of energy of product. aligned H = & (606.10+4 410.5+431.37) & -(6 410.50+336.49) & =-120.0 ~kJ / mol aligned

From the following bond energies : H - H bond energy : 431.37 ~kJ ~mol ⁻¹ C = C bond energy : 606.10 ~kJ ~mol ⁻¹ C - C bond energy : 336.49 ~kJ ~mol ⁻¹ C - H bond energy : 410.50 ~kJ ~mol ⁻¹ Enthalpy for the reaction, will be :

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