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NEET2008ChemistryThermodynamics (C)Actual

Bond dissociation enthalpy of H ₂, Cl ₂ and HCl are 434,242 and 431 kJmol ⁻ ^1 respectively. Enthalpy of formation of HCl is

Options

  1. A245 kJmol ⁻¹
  2. B93 kJmol ⁻¹
  3. C-245 kJmol ⁻¹
  4. D-93 kJmol ⁻¹

Correct answer

D. -93 kJmol ⁻¹

Step-by-step solution

aligned & 2[ H ]+2[ Cl ] 2 HCl , H =-862 ~kJ ~mol ⁻¹ & H ₂ 2[ H ], H =434 ~kJ & Cl ₂ 2[ Cl ], H =242 ~kJ & H ₂+ Cl ₂ 2 HCl , H =-186 ~kJ & H ₄ of HCl = -186 2 =-93 ~kJ ~mol ⁻¹ aligned

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