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NEET 2007
Exam
NEET
Year
2007
Subject
Chemistry
Chapter
Thermodynamics (C)

NEET 2007 · Chemistry · Thermodynamics (C)

Consider the following reactions: (i) H_ (a q) ^ + +OH_ (a q) ^ -...

Consider the following reactions: (i) H(aq)++OH(aq)−→H2O(i),ΔH=−X1 kJ mol−1\mathrm{H}_{(a q)}^{+}+\mathrm{OH}_{(a q)}^{-} \rightarrow \mathrm{H}_2 \mathrm{O}_{(\mathrm{i})}, \Delta \mathrm{H} =-\mathrm{X}_1 \mathrm{~kJ} \mathrm{~mol}^{-1} (ii) \mathrm{H}_{2(a q)}+\frac{1}{2} \mathrm{O}_{2(a q)} \rightarrow \mathrm{H}_2 \mathrm{O}_{(\mathrm{I})} \Delta \mathrm{H} =-\mathrm{X}_2 \mathrm{~kJ} \mathrm{~mol}^{-1} (iii) CO2( g)+H2(g)→CO(g)+H2O,ΔH=−X3 kJ mol−1\mathrm{CO}_{2(\mathrm{~g})}+\mathrm{H}_{2(g)} \rightarrow \mathrm{CO}_{(g)}+\mathrm{H}_2 \mathrm{O}, \Delta \mathrm{H} =-\mathrm{X}_3 \mathrm{~kJ} \mathrm{~mol}^{-1} (iv) C2H2(g)+52O2(g)→2CO2(g)+H2O(i), ΔH=+X4 kJ mol−1\mathrm{C}_2 \mathrm{H}_{2(g)}+\frac{5}{2} \mathrm{O}_{2(g)} \rightarrow 2 \mathrm{CO}_{2(g)}+\mathrm{H}_2 \mathrm{O}_{(i) \text{, }} \Delta \mathrm{H}=+\mathrm{X}_4 \mathrm{~kJ} \mathrm{~mol}^{-1} Enthalpy of formation of H2O(l)\mathrm{H}_2 \mathrm{O}_{(l)} is:

Options

  1. A+X3 kJ mol−1+\mathrm{X}_3 \mathrm{~kJ} \mathrm{~mol}^{-1}
  2. B−X4 kJ mol−1-\mathrm{X}_4 \mathrm{~kJ} \mathrm{~mol}^{-1}
  3. C+X1 kJ mol−1+\mathrm{X}_1 \mathrm{~kJ} \mathrm{~mol}^{-1}
  4. D−X2 kJmol−1-\mathrm{X}_2 \mathrm{~kJ}^{\mathrm{mol}}{ }^{-1}

Correct answer

D. −X2 kJmol−1-\mathrm{X}_2 \mathrm{~kJ}^{\mathrm{mol}}{ }^{-1}

Step-by-step solution

The given reaction represents the formation of H2O\mathrm{H}_2 \mathrm{O}, and the X2\mathrm{X}_2 represents the enthalpy of formation of H2O\mathrm{H}_2 \mathrm{O}. The enthalpy of formation is the heat evolved or absorbed when one mole of substance is formed from its constituent atoms. Related Theory A negative enthalpy change represents an exothermic change where energy is released from the reaction, a positive enthalpy change represents an endothermic reaction where energy is taken in from the surroundings.
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