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NEET 2006
Exam
NEET
Year
2006
Subject
Chemistry
Chapter
Thermodynamics (C)

NEET 2006 · Chemistry · Thermodynamics (C)

The enthalpy of hydrogenation of cyclohexene is -119.5 ~kJ ~mol^ -1...

The enthalpy of hydrogenation of cyclohexene is −119.5 kJ mol−1-119.5 \mathrm{~kJ} \mathrm{~mol}^{-1}. If resoance energy of benzene is -150 kJmol−1\mathrm{kJ} \mathrm{mol}^{-1}, its enthalpy of hydrogenation would be:

Options

  1. A−358.5 kJ mol−1-358.5 \mathrm{~kJ} \mathrm{~mol}^{-1}
  2. B−508.9 kJ mol−1-508.9 \mathrm{~kJ} \mathrm{~mol}^{-1}
  3. C−208.1 kJ mol−1-208.1 \mathrm{~kJ} \mathrm{~mol}^{-1}
  4. D−269.9 kJ mol−1-269.9 \mathrm{~kJ} \mathrm{~mol}^{-1}

Correct answer

C. −208.1 kJ mol−1-208.1 \mathrm{~kJ} \mathrm{~mol}^{-1}

Step-by-step solution

∴\therefore Heat of hydrogenation of cyclohaxene =−119.5 kJ/mol=-119.5 \mathrm{~kJ} / \mathrm{mol} ∴\therefore Heat of hydrogenation of benzene =3×−119.5=−358.5 kJ/mol=3 \times-119.5=-358.5 \mathrm{~kJ} / \mathrm{mol} Resonance energy = Observed ΔH−\Delta \mathrm{H}- Calculated ΔH\Delta \mathrm{H} =−150.4=−358.5−x=-150.4=-358.5-x x=−208.1 kJx=-208.1 \mathrm{~kJ} Related Theory The energy calculated for a resonance hybrid is lower than the energies of any of the alternative structures; the molecule is then said to be stabilized by resonance.
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