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NEET 2012
Exam
NEET
Year
2012
Subject
Physics
Chapter
Alternating Current

NEET 2012 · Physics · Alternating Current

The instantaneous values of alternating current and voltages in a...

The instantaneous values of alternating current and voltages in a circuit are given as i=12sin⁡(100\pit) ampere e=12sin⁡(100\pit+π/3) volt \begin{aligned}& i=\frac{1}{\sqrt{2}} \sin (100 \pit) \text{ ampere }\\ & e=\frac{1}{\sqrt{2}} \sin (100 \pit+\pi/ 3) \text{ volt } \end{aligned}The average power in Watts consumed in the circuit is

Options

  1. A14\frac{1}{4}
  2. B34\frac{\sqrt{3}}{4}
  3. C12\frac{1}{2}
  4. D18\frac{1}{8}

Correct answer

D. 18\frac{1}{8}

Step-by-step solution

Given equations i=12sin⁡(100πt)i=\frac{1}{\sqrt{2}} \sin (100 \pi t) and e=12sin⁡(100πt+π/3)∴io=12e=\frac{1}{\sqrt{2}} \sin (100 \pi t+\pi / 3) \therefore \quad i_o=\frac{1}{\sqrt{2}} and Vo=12V_o=\frac{1}{\sqrt{2}} We know that average power \begin{aligned} & P_{\mathrm{av}}=V_{\mathrm{rms}} \times i_{\mathrm{rms}} \cos \phi \\ &=\frac{1}{2} \times \frac{1}{2} \times \cos 60^{\circ} \\ & \qquad\left[\because i_{\mathrm{rms}}=\frac{i_o}{\sqrt{2}} \text{ and } V_{\mathrm{rms}}=\frac{V_o}{\sqrt{2}}\right] \\ &=\frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \\ &=\frac{1}{8} \mathrm{~W} \end{aligned}
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