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NEET 2020
Exam
NEET
Year
2020
Subject
Physics
Chapter
Alternating Current

NEET 2020 · Physics · Alternating Current

A 40μ F capacitor is connected to a 200V , 50Hz AC supply. The rms...

A 40μF40\mu F capacitor is connected to a 200V200V, 50Hz50Hz AC supply. The rms value of the current in the circuit is, nearly:

Options

  1. A2.05A2.05A
  2. B2.5A2.5A
  3. C25.1A25.1A
  4. D1.7A1.7A

Correct answer

B. 2.5A2.5A

Step-by-step solution

Current flowing through the capacitor is given by,Irms=VXC=V1/Cω=VCω{I}_{rms} = \dfrac{V}{{X}_{C}} = \dfrac{V}{1 / C\omega} = VC\omega

⇒Irms=200×40×10−6×2π×50⇒ {I}_{rms} = 200 \times 40 \times {10}^{- 6} \times 2\pi \times 50

⇒Irms=2.5A⇒ {I}_{rms} = 2.5A

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