NEET2009PhysicsAlternating CurrentActual
Power dissipated in an L-C-R series circuit connected to an AC source of emf is
Options
- A^2 R [R^2+ (L - 1 C )^2 ]
- B^2 R ^2+ ( L - 1 C )^2 R
- C^2 [ R ^2+ ( L - 1 C )^2 ] R
- D^2 R R^2+ (L - 1 C )^2
Correct answer
A. ^2 R [R^2+ (L - 1 C )^2 ]
Step-by-step solution
The emf of an LCR circuit is ( ). The impedance of a series LCR circuit is given as, (Z= [R^2+ ( L- 1 C )^2 ] ) The power factor in a series LCR circuit is given as, ( = R | Z | ) The power dissipated in the circuit is given as, ( aligned & P = V _ rms I _ rms & = | Z | R | Z | & = ^2 R [ R ^2+ ( L - 1 C )^2 ] aligned ) Thus, the power dissipated in the series (L C R ) circuit is ( ^2 R [R^2+ ( L- 1 C )^2 ] ).