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NEET2009PhysicsAlternating CurrentActual

Power dissipated in an L-C-R series circuit connected to an AC source of emf is

Options

  1. A^2 R [R^2+ (L - 1 C )^2 ]
  2. B^2 R ^2+ ( L - 1 C )^2 R
  3. C^2 [ R ^2+ ( L - 1 C )^2 ] R
  4. D^2 R R^2+ (L - 1 C )^2

Correct answer

A. ^2 R [R^2+ (L - 1 C )^2 ]

Step-by-step solution

The emf of an LCR circuit is ( ). The impedance of a series LCR circuit is given as, (Z= [R^2+ ( L- 1 C )^2 ] ) The power factor in a series LCR circuit is given as, ( = R | Z | ) The power dissipated in the circuit is given as, ( aligned & P = V _ rms I _ rms & = | Z | R | Z | & = ^2 R [ R ^2+ ( L - 1 C )^2 ] aligned ) Thus, the power dissipated in the series (L C R ) circuit is ( ^2 R [R^2+ ( L- 1 C )^2 ] ).

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