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NEET 2008
Exam
NEET
Year
2008
Subject
Physics
Chapter
Alternating Current

NEET 2008 · Physics · Alternating Current

In an A C circuit the emf (e) and the current (i) at any instant...

In an ACA C circuit the emf (e) and the current (i) at any instant are given respectively by e=E0sin⁡ωte=E_0 \sin \omega t i=I0sin⁡(ωt−ϕ)i=I_0 \sin (\omega t-\phi) The average power in the circuit over one cycle of AC is

Options

  1. AE0I02\frac{E_0 I_0}{2}
  2. BE0I02sin⁡ϕ\frac{E_0 I_0}{2} \sin \phi
  3. CE0I02cos⁡ϕ\frac{E_0 I_0}{2} \cos \phi
  4. DE0I0E_0 I_0

Correct answer

C. E0I02cos⁡ϕ\frac{E_0 I_0}{2} \cos \phi

Step-by-step solution

Key Idea: The power is defined as the rate at which work is being done in the circuit. Power = rate of work done in one complete cycle. Paν=WTPaν=(E0I0cos⁡ϕ)T/2TPaν=E0I0cos⁡ϕ2\begin{aligned} & P_{a \nu}=\frac{W}{T} \\ & P_{a \nu}=\frac{\left(E_0 I_0 \cos \phi\right) T / 2}{T} \\ & P_{a \nu}=\frac{E_0 I_0 \cos \phi}{2} \end{aligned} where cos⁡ϕ\cos \phi is called the power factor of an AC circuit.
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