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NEET 2007
Exam
NEET
Year
2007
Subject
Physics
Chapter
Alternating Current

NEET 2007 · Physics · Alternating Current

What is the value of inductance L for which the current is maximum...

What is the value of inductance LL for which the current is maximum in a series LCR circuit with C=10μFC=10 \mu \mathrm{F} and ω=1000\omega=1000 s−1\mathrm{s}^{-1} ?

Options

  1. A1mH1 \mathrm{mH}
  2. Bcannot be calculated unless RR is known
  3. C10mH10 \mathrm{mH}
  4. D100mH100 \mathrm{mH}.

Correct answer

D. 100mH100 \mathrm{mH}.

Step-by-step solution

According to question current is maximum at resonance ⇒ω2=1LC⇒L=1ω2C=1(1000)2(10×10−6)=0.1H=100mH\begin{aligned} \Rightarrow \quad \omega^2 & =\frac{1}{L C} \\ \Rightarrow \quad L & =\frac{1}{\omega^2 C} \\ & =\frac{1}{(1000)^2\left(10 \times 10^{-6}\right)} \\ & =0.1 \mathrm{H}=100 \mathrm{mH} \end{aligned}
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