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NEET 2003
Exam
NEET
Year
2003
Subject
Physics
Chapter
Alternating Current

NEET 2003 · Physics · Alternating Current

An electric kettle has two heating coils. When one of the coils is...

An electric kettle has two heating coils. When one of the coils is connected to a.c. source, the water in the kettle boils in 10 minute. When the other coil is used the water boils in 40 minute. If both the coils are connected in parallel, the time taken by the same quantity of water to boil will be:An electric kettle has two heating coils. When one of the coils is connected to a.c. source, the water in the kettleAn electric kettle has two heating coils. When one of the coils is connected to a.c. source, the water in the kettle

Options

  1. A8 minute
  2. B4 minute
  3. C25 minute
  4. D15 minute

Correct answer

A. 8 minute

Step-by-step solution

An electric kettle has two heating coils. When one of the coils is connected to a.c. source, the water in the kettle
Here Q=V2R1×t1=V2R2×t2Q=\frac{V^2}{R_1} \times t_1=\frac{V^2}{R_2} \times t_2=V2R\timest∴1R=1R1+1R2⇒QV2t=QV2t1+QV2t2⇒1t=1t1+1t4⇒t=t1t2t1+t2=10×4010+40=8 min\begin{aligned}& =\frac{V^2}{R} \timest \\ & \therefore \quad \frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}\\ & \Rightarrow \quad \frac{Q}{V^2 t}=\frac{Q}{V^2 t_1}+\frac{Q}{V^2 t_2}\\ & \Rightarrow \quad \frac{1}{t}=\frac{1}{t_1}+\frac{1}{t_4}\\ & \Rightarrow \quad t=\frac{t_1 t_2}{t_1+t_2}\\ & =\frac{10 \times 40}{10+40}=8 \mathrm{~min}\\ & \end{aligned}$
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