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NEET2002PhysicsAlternating CurrentActual

For a series LCR circuit the power loss at resonance is:

Options

  1. AV^2 ( L- 1 C )
  2. Br L
  3. CI^2 R
  4. DV^2 C

Correct answer

C. I^2 R

Step-by-step solution

Power loss is given by P=V I At resonance current and voltage are in the same phase, that is =0 . P=V I 0=V I=I^2 R

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