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NEET 2002
Exam
NEET
Year
2002
Subject
Physics
Chapter
Alternating Current

NEET 2002 · Physics · Alternating Current

For a series LCR circuit the power loss at resonance is:

For a series LCR circuit the power loss at resonance is:

Options

  1. A\frac{V^2}{\left(\omega L-\frac{1}{\omega C}\right)}
  2. BrLωr L \omega
  3. CI2RI^2 R
  4. DV2Cω\frac{V^2}{C \omega}

Correct answer

C. I2RI^2 R

Step-by-step solution

Power loss is given by P=V I \cos \phi At resonance current and voltage are in the same phase, that is ϕ=0\phi=0. \therefore P=V I \cos 0=V I=I² R
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