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NEET 2007
Exam
NEET
Year
2007
Subject
Physics
Chapter
Alternating Current

NEET 2007 · Physics · Alternating Current

The primary and secondary coils of a transformer have 50 and 1500...

The primary and secondary coils of a transformer have 50 and 1500 turns respectively. If the magnetic flux ϕ\phi linked with the primary coil is given by ϕ=ϕv+4t\phi=\phi_v+4 t, where ϕ\phi is in webers, tt is time in seconds and ϕv\phi_v is a constant, the output voltage across the output voltage across the secondary coil is:

Options

  1. A120 volts
  2. B220 volts
  3. C30 volts
  4. D90 volts.

Correct answer

A. 120 volts

Step-by-step solution

The magnetic flux linked with the primary coil is given by (\phi=\phi_0+4 t) So, voltage across primary Vp=dϕdt=ddt(ϕ0+4t)=4 volt (as ϕ0= constant )\begin{aligned} & V_p=\frac{d \phi}{d t}=\frac{d}{d t}\left(\phi_0+4 t\right) \\ & \left.=4 \text{ volt (as } \phi_0=\text{ constant }\right) \end{aligned}) Also, we have (N_p=50 \text{\text{ and } }Ns=1500)Fromrelation,N_s=1500) From relation,VsVp=NsNpor Vs=VpNsNp=4(150050)=120V\begin{aligned} &\frac{V_s}{V_p}=\frac{N_s}{N_p} \\ & \text{or } V_s=V_p \frac{N_s}{N_p} \\ & =4 \left(\frac{1500}{50}\right) \\ & =120 \mathrm{ V} \end{aligned}$)
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