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NEET 2025
Exam
NEET
Year
2025
Subject
Physics
Chapter
Atomic Physics

NEET 2025 · Physics · Atomic Physics

De-Broglie wavelength of an electron orbiting in the n=2 state of...

De-Broglie wavelength of an electron orbiting in the n=2n=2 state of hydrogen atom is close to (Given Bohr radius =0.052 nm=0.052 \mathrm{~nm} )

Options

  1. A0.067 nm
  2. B0.67 nm
  3. C1.67 nm
  4. D2.67 nm

Correct answer

B. 0.67 nm

Step-by-step solution

Given n=2,Z=1\mathrm{n}=2, \mathrm{Z}=12πr=nλ2π×(0.052n2Z)=nλ\begin{aligned} & 2 \pi \mathrm{r}=\mathrm{n} \lambda \\ & 2 \pi \times\left(0.052 \frac{\mathrm{n}^2}{\mathrm{Z}}\right)=\mathrm{n} \lambda \end{aligned}$OnsolvingOn solving\lambda=0.67 \mathrm{~nm}$
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