Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NEET2023PhysicsAtomic PhysicsActual

The ground state energy of hydrogen atom is -13.6 eV . The energy needed to ionize hydrogen atom from its second excited state will be

Options

  1. A1.51 eV
  2. B3.4 eV
  3. C13.6 eV
  4. D6.8 eV

Correct answer

A. 1.51 eV

Step-by-step solution

We know that total energy of electron in hydrogen atom is given by E_ = -13.6 n^2 Also, total energy of electron in second excited state = -13.6 (3)^2 =-1.51 eV lonization energy or energy required to ionize hydrogen atom from its second excited state =1.51 eV

Practice Atomic Physics on Quantrex Academy →

More from Atomic Physics

The energy levels of certain atom are represented in the following figure. During the transition from 2E to E level, a photon of wavelength is emitted. The wavelength of photon pro 2026The ratio of ionization energy of a hydrogen atom in fifth excited state to second excited state is 2026The wavelength of radiation emitted is ' ' when an electron jumps from second to first orbit of hydrogen atom. For the electron to jump from third to first orbit of hydrogen atom, 2026The angular momentum of an electron in Bohr's hydrogen atom having energy -0.544 eV is (h = Planck's constant) 2026An electron of mass ' m_e ' and charge ' e ' revolving around the nucleus in n^ th orbit has orbital magnetic moment enh 4 m_e which is equal to Bohr Magneton, the orbit number in 2026The ratio of angular frequency ( ) of an electron to the total energy ( E) of an electron in the first orbit of hydrogen atom is ( h is the Plank's constant) 2026The ratio between the areas of Bohr's first three orbits of the hydrogen atom are 2026A hydrogen atom in its ground state is irradiated by light of wavelength 1026 Å . The electron gets excited to higher energy state n . Given the ground state energy is -13.6 eV and 2026 Full Atomic Physics list All NEET PYQs