The ground state energy of hydrogen atom is -13.6 eV . The energy needed to ionize hydrogen atom from its second excited state will be

Correct answer: A. 1.51 eV We know that total energy of electron in hydrogen atom is given by E_ =(-13.6)/(n^2) Also, total energy of electron in second excited state =(-13.6)/((3)^2)=-1.51 eV lonization energy or energy required to ionize hydrogen atom from its second excited state =1.51 eV

NEET 2023

Exam: NEET
Year: 2023
Subject: Physics
Chapter: Atomic Physics

NEET 2023 · Physics · Atomic Physics

The ground state energy of hydrogen atom is -13.6 eV . The energy...

The ground state energy of hydrogen atom is

-13.6 \mathrm{eV}

. The energy needed to ionize hydrogen atom from its second excited state will be

Options

A $1.51 \mathrm{eV}$
B $3.4 \mathrm{eV}$
C $13.6 \mathrm{eV}$
D $6.8 \mathrm{eV}$

Correct answer

A. $1.51 \mathrm{eV}$

Step-by-step solution

We know that total energy of electron in hydrogen atom is given by

E_\eta=\frac{-13.6}{n^2}

Also, total energy of electron in second excited state

=\frac{-13.6}{(3)^2}=-1.51 \mathrm{eV}

\Rightarrow

lonization energy or energy required to ionize hydrogen atom from its second excited state

=1.51 \mathrm{eV}

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