The ionization energy of the electron in the hydrogen atom in its ground state is 13.6 eV . The atoms are excited to higher energy levels to emit radiations of 6 wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between

Step-by-step solution

Key Idea Number of spectral lines abtained due to transition of electron from n ^ th orbit to lower orbit is N = n ( n -1) 2 and for maximum wavelength the difference between the orbits of the series should be minimum. Number of spectral lines N = n ( n -1) 2 aligned & n(n-1) 2 & =6 or & n^2-n-12 & =0 or & (n-4)(n+3) & =0 or & n & =4 aligned Now as the first line of the series has the maximum wavelength, therefore electron jumps from the 4^ th orbit to the third orbit.