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NEET 2005
Exam
NEET
Year
2005
Subject
Physics
Chapter
Atomic Physics

NEET 2005 · Physics · Atomic Physics

The total energy of an electron in the first excited state of...

The total energy of an electron in the first excited state of hydrogen atom is about −3.4eV-3.4 \mathrm{eV}. Its kinetic energy in this state is:

Options

  1. A3.4eV3.4 \mathrm{eV}
  2. B6.8eV6.8 \mathrm{eV}
  3. C−3.4eV-3.4 \mathrm{eV}
  4. D−6.8eV-6.8 \mathrm{eV}

Correct answer

A. 3.4eV3.4 \mathrm{eV}

Step-by-step solution

\mathrm{K} . \mathrm{E} .=\left|\frac{1}{2}P . E\right| But P.E is negative∴ Total energy =∣12P\cdotE∣−P\cdotE=−P⋅E2=−3.4eVK.E=+3.4eV\begin{aligned} \therefore\text{ Total energy }& =\left|\frac{1}{2}P \cdotE\right|-P \cdotE \\ & =-\frac{P \cdot E}{2}=-3.4 \mathrm{eV}\\ \mathrm{K} . \mathrm{E}& =+3.4 \mathrm{eV} \end{aligned}$
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