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The total energy of electron in the ground state of hydrogen atom is -13.6 eV . The kinetic energy of an electron in the first excited state is:

Options

  1. A6.8 eV
  2. B13.6 eV
  3. C1.7 eV
  4. D-3.4 eV .

Correct answer

D. -3.4 eV .

Step-by-step solution

Energy of n^ th orbit of hydrogen atom is given by E_n=- 13.6 n^2 e V for ground state n=1E₁=- 13.6 12 =-13.6 eV for excited state n=2E₂=- 13.6 22 =-3.4 eV

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