The total energy of electron in the ground state of hydrogen atom is -13.6 eV . The kinetic energy of an electron in the first excited state is:

Correct answer: D. -3.4 eV . Energy of n^ th orbit of hydrogen atom is given by E_n=-(13.6)/(n^2) e V for ground state n=1 E_1=-(13.6)/(12)=-13.6 eV for excited state n=2 E_2=-(13.6)/(22)=-3.4 eV

NEET 2007

Exam: NEET
Year: 2007
Subject: Physics
Chapter: Atomic Physics

NEET 2007 · Physics · Atomic Physics

The total energy of electron in the ground state of hydrogen atom...

The total energy of electron in the ground state of hydrogen atom is

-13.6 \mathrm{eV}

. The kinetic energy of an electron in the first excited state is:

Options

A $6.8 \mathrm{eV}$
B $13.6 \mathrm{eV}$
C $1.7 \mathrm{eV}$
D $-3.4 \mathrm{eV}$ .

Correct answer

D. $-3.4 \mathrm{eV}$ .

Step-by-step solution

Energy of

n^{\text{th }}

orbit of hydrogen atom is given by

E_n=-\frac{13.6}{n^2} e V

for ground state

n=1 E_1=-\frac{13.6}{12}=-13.6 \mathrm{eV}

for excited state

n=2 E_2=-\frac{13.6}{22}=-3.4 \mathrm{eV}

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