If the plates of a parallel plate capacitor connected to a battery are moved close to each other, then A. the charge stored in it, increases. B. the energy stored in it, decreases. C. its capacitance increases. D. the

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Correct answer: A. A, C and E only

Given V=V= Constant (i) aligned & C^ = _0 A d^ , C=( _0 A)/(d) & d^ < d & C^ aligned Hence, final capacitance greater than initial capacitance, (ii) aligned U^ & =(1)/(2) C^ V^2 U & =(1)/(2) C V^2 U^ & aligned Hence final energy is greater than initial energy (iii) aligned & Q^ V^ =C^ and (Q)/(V)=C & Q^ V^ ≠ (Q)/(V) aligned (iv) Product of charge and voltage aligned & X^ =Q^ V=C^ V^2 & X=Q V=C V^2 & X^ aligned

If the plates of a parallel plate capacitor connected to a battery...

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