A parallel plate air capacitor has capacity C , distance of separation between plates is d and potential difference V is applied between the plates. The force of attraction between the plates of the capacitor is

Correct answer: A. C V ^ 2 2d . Attraction force between the plates, F = q ^ 2 2A ε _ 0 where q = CV and C = ε _ 0 A d ⇒ F = C ^ 2 V ^ 2 2Cd = C V ^ 2 2d

NEET 2015

Exam: NEET
Year: 2015
Subject: Physics
Chapter: Capacitance

NEET 2015 · Physics · Capacitance

A parallel plate air capacitor has capacity C , distance of...

A parallel plate air capacitor has capacity

\text{C}

, distance of separation between plates is

\text{d}

and potential difference

\text{V}

is applied between the plates. The force of attraction between the plates of the capacitor is

Options

A $\dfrac{C{V}^{2}}{2d}$ .
B $\dfrac{C{V}^{2}}{d}$ .
C $\dfrac{{C}^{2}{V}^{2}}{2{d}^{2}}$ .
D $\dfrac{{C}^{2}{V}^{2}}{2d}$ .

Correct answer

A. $\dfrac{C{V}^{2}}{2d}$ .

Step-by-step solution

Attraction force between the plates,

F = \dfrac{{q}^{2}}{2A{ε}_{0}}

where

q = CV

and

C = \dfrac{{ε}_{0}A}{d}

⇒ F = \dfrac{{C}^{2}{V}^{2}}{2Cd} = \dfrac{C{V}^{2}}{2d}

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