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NEET 2014
Exam
NEET
Year
2014
Subject
Physics
Chapter
Capacitance

NEET 2014 · Physics · Capacitance

Two thin dielectric slabs of dielectric constants K _ 1 and K _ 2 (...

Two thin dielectric slabs of dielectric constants K1{K}_{1} and K2{K}_{2}\left({K}_{1} < {K}_{2}\right)are inserted between plates of a parallel plate capacitor, as shown in the figure. The variation of electric field &lsquo;E&rsquo; between the plates with distance &lsquo;d&rsquo; as measured from plateP is correctly shown by:
Two thin dielectric slabs of dielectric constants K _ 1 and K _ 2 ( K _ 1

Options

  1. AIf the number of available constraints is 3 and the number of parameters to be optimise is 4 , then
  2. BIf the number of available constraints is 3 and the number of parameters to be optimise is 4 , then
  3. CIf the number of available constraints is 3 and the number of parameters to be optimise is 4 , then
  4. DIf the number of available constraints is 3 and the number of parameters to be optimise is 4 , then

Correct answer

C. If the number of available constraints is 3 and the number of parameters to be optimise is 4 , then

Step-by-step solution

Here we have to calculate the graph between E and d in the given situation

Two thin dielectric slabs of dielectric constants K _ 1 and K _ 2 ( K _ 1

We know that in dielectric E becomes E/k

where

E = Electric fjeld

k = Dielectric constants

Since (K1<K2)\left({K}_{1} < {K}_{2}\right), The third option will be correct.
Two thin dielectric slabs of dielectric constants K _ 1 and K _ 2 ( K _ 1

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