Two thin dielectric slabs of dielectric constants K 1 and K 2 K 1 < K 2 are inserted between plates of a parallel plate capacitor, as shown in the figure. The variation of electric field ‘ E ’ between the plates with distanc

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Two thin dielectric slabs of dielectric constants K 1 and K 2 K 1 &#60; K 2 are inserted between plates of a parallel plate capacitor, as shown in the figure. The variation of electric field &lsquo; E &rsquo; between the plates with distance &lsquo; d &rsquo; as measured from plate P is correctly shown by:

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Correct answer: 2

Here we have to calculate the graph between E and d in the given situation We know that in dielectric E becomes E/k where E = Electric fjeld k = Dielectric constants Since K 1 &#60; K 2 , The third option will be correct.

Two thin dielectric slabs of dielectric constants K 1 and K 2 K 1 < K 2 are inserted between plates of a parallel plate capacitor, as shown in the figure. The variation of electric field ‘ E ’ between the plates with distance ‘ d ’ as measured from plate P is correctly shown by:

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