The energy required to charge a parallel plate condenser of plate separation d and plate area of cross-section A such that the uniform electric field between the plates is E , is

Step-by-step solution

Energy given by the cell E=C V^2 Here, C= capacitance of condenser = A ₀ d V= potential difference across the plates =E d Therefore, aligned E & = ( A ₀ d )(E d)^2 & =A ₀ E^2 d aligned