NEET2010PhysicsCenter of Mass, Momentum and CollisionActual
A man of 50 ~kg mass is standing in a gravity free space at a height of 10 ~m above the floor. He throws a stone of 0.5 ~kg mass downwards with a speed 2 ~ms ⁻¹ . When the stone reaches the floor, the distance of the man above the floor will be
Options
- A9.9 ~m
- B10.1 ~m
- C10 ~m
- D20 ~m
Correct answer
B. 10.1 ~m
Step-by-step solution
m r= constant aligned m₁ r₁ & =m₂ r₂ r₂ & = m₁ r₁ m₂ & = 0.5 10 50 =0.1 aligned The distance of the man above the floor (total height )=10+0.1=10.1 ~m .