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NEET 2004

Exam: NEET
Year: 2004
Subject: Physics
Chapter: Center of Mass, Momentum and Collision

NEET 2004 · Physics · Center of Mass, Momentum and Collision

Consider a system of two particle having masses m_1 and m_2 . If...

Consider a system of two particle having masses

m_1

and

m_2

. If the particle of mas

m_1

is pushed towards the mass centre of particle through a distance

d

, by what distance would the particle of mass

m_2

move so as to keep the mass centre of particles at the original position?

Options

A $\frac{m_1}{m_1+m_2} d$
B $\frac{m_1}{m_2} d$
C $d$
D $\frac{m_2}{m_1} d$

Correct answer

B. $\frac{m_1}{m_2} d$

Step-by-step solution

We know that

\mathrm{CM}=\frac{m_1 x_1+m_2 x_2}{m_1+m_2}

After changing a position of

m_1

and to keep the position of C.M. same. C.M.

=\frac{m_1

\left(x_1 d\right)+m_2\left(\mathrm{x}_2-d_2\right)}{m_1+m_2}

\begin{aligned}0 & =\frac{m_1 d-m_2 d_2}{m_1+m_2}\\ \Rightarrow d_2 & =\frac{m_1}{m_2}d \end{aligned}

$

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