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NEET 2004
Exam
NEET
Year
2004
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

NEET 2004 · Physics · Center of Mass, Momentum and Collision

A particle of mass m_1 is moving with a velocity v_1 and another...

A particle of mass m1m_1 is moving with a velocity v1v_1 and another particle of mass m2m_2 is moving with a velocity v2v_2. Both of them have the same momentum but their different kinetic energies are E1E_1 and E2E_2 respectively. If m1>m2m_1>m_2 then:

Options

  1. AE1<E2E_1 < E_2
  2. BE1E2=m1m1\frac{E_1}{E_2}=\frac{m_1}{m_1}
  3. CE1>E2E_1>E_2
  4. DE1=E2E_1=E_2

Correct answer

A. E1<E2E_1 < E_2

Step-by-step solution

We know that K.E. =P22m=\frac{P^2}{2 m} ∴E1E2=P12/2m1P22/2m2⇒E1E2=m2m1\begin{array}{ll} \therefore& \frac{E_1}{E_2}=\frac{P_1^2 / 2 m_1}{P_2^2 / 2 m_2}\\ \Rightarrow \quad \frac{E_1}{E_2}=\frac{m_2}{m_1} \end{array}Here m1=m2\quad m_1=m_2 \therefore \quad E_1 < E_2
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