NEET2004PhysicsCenter of Mass, Momentum and CollisionActual
A particle of mass m₁ is moving with a velocity v₁ and another particle of mass m₂ is moving with a velocity v₂ . Both of them have the same momentum but their different kinetic energies are E₁ and E₂ respectively. If m₁>m₂ then:
Options
- AE₁ < E₂
- BE₁ E₂ = m₁ m₁
- CE₁>E₂
- DE₁=E₂
Correct answer
A. E₁ < E₂
Step-by-step solution
We know that K.E. = P^2 2 m array ll & E₁ E₂ = P₁^2 / 2 m₁ P₂^2 / 2 m₂ E₁ E₂ = m₂ m₁ array Here m₁=m₂ E₁ < E₂