In an electrical circuit, the voltage is measured as V=(200 ± 4) volt and the current is measured as I=(20 ± 0.2) A . The value of the resistance is:

Correct answer: B. (10 ± 0.3) R=(V)/(l)=(200)/(20)=10 (Δ R)/(R)=(Δ V)/(V)+(Δ l)/(l)=(4)/(200)+(0.2)/(20)=(4+2)/(200)=(6)/(200) Δ R=(6)/(200) × R=(6)/(20)=(3)/(10)=0.3 Resistance =R ± Δ R=(10 ± 0.3)

NEET 2024

Exam: NEET
Year: 2024
Subject: Physics
Chapter: Current Electricity

NEET 2024 · Physics · Current Electricity

In an electrical circuit, the voltage is measured as V=(200 ± 4)...

In an electrical circuit, the voltage is measured as

V=(200 \pm 4)

volt and the current is measured as

I=(20 \pm 0.2) \mathrm{A}

. The value of the resistance is:

Options

A $(10 \pm 4.2) \Omega$
B $(10 \pm 0.3) \Omega$
C $(10 \pm 0.1) \Omega$
D $(10 \pm 0.8) \Omega$

Correct answer

B. $(10 \pm 0.3) \Omega$

Step-by-step solution

R=\frac{V}{l}=\frac{200}{20}=10 \Omega

\frac{\Delta R}{R}=\frac{\Delta V}{V}+\frac{\Delta l}{l}=\frac{4}{200}+\frac{0.2}{20}=\frac{4+2}{200}=\frac{6}{200}

\Rightarrow \Delta R=\frac{6}{200} \times R=\frac{6}{20}=\frac{3}{10}=0.3 \Omega

\therefore

Resistance

=R \pm \Delta R=(10 \pm 0.3) \Omega

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