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NEET 2024

Exam: NEET
Year: 2024
Subject: Physics
Chapter: Current Electricity

NEET 2024 · Physics · Current Electricity

A wire of length ' 1 and resistance 100 is divided into 10 equal...

A wire of length ' 1 and resistance

100 \Omega

is divided into 10 equal parts. The first 5 parts are connected in series while the next 5 parts are connected in parallel. The two combinations are again connected in series. The resistance of this final combination is:

Options

A $52 \Omega$
B $55 \Omega$
C $60 \Omega$
D $26 \Omega$

Correct answer

A. $52 \Omega$

Step-by-step solution

Divided into 10 parts

\begin{aligned} R & =\frac{\rho l}{A} \\ R^{\prime} & =\frac{\rho l}{10 A}=\frac{R}{10} \\ R_S & =5 \times \frac{R}{10} \quad \text{ [series] } \\ R_S & =50 \\ R_P & =\frac{R}{50} \quad \text{ [parallel] } \\ R_{\text{eq }} & =R_S+R_P \\ & =52 \Omega \end{aligned}

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