NEET2024PhysicsCurrent ElectricityActual
A wire of length ' 1 and resistance 100 is divided into 10 equal parts. The first 5 parts are connected in series while the next 5 parts are connected in parallel. The two combinations are again connected in series. The resistance of this final combination is:
Options
- A52
- B55
- C60
- D26
Correct answer
A. 52
Step-by-step solution
Divided into 10 parts aligned R & = l A R^ & = l 10 A = R 10 R_S & =5 R 10 [series] R_S & =50 R_P & = R 50 [parallel] R_ eq & =R_S+R_P & =52 aligned