NEET2026PhysicsCurrent ElectricityActual
A uniform metallic wire having resistance 4 is bent to form a square loop (ABCD) (see figure). A resistance of 2 is connected between points B and D and a battery of 2 V is connected across points A and C as shown in the figure. Now the value of current ( I ) is :
Options
- A2 A
- B8 A
- C4.5 A
- D4 A
Correct answer
A. 2 A
Step-by-step solution
The total resistance of the uniform wire is 4 . Since it is bent to form a square loop ABCD, the resistance of each of its four sides is equal. Resistance of each side = 4 4 = 1 . Thus, R_ AB = R_ BC = R_ CD = R_ DA = 1 . The given circuit can be redrawn as a Wheatstone bridge where the arms are AB, BC, AD, and DC, and the central arm is BD. The battery is connected across the opposite corners A and C. Let's check the balance condition of the Wheatstone bridge: R_ AB R_ AD = 1 1 = 1 R_ BC R_ DC = 1 1 = 1 Since R_ A