In a potentiometer circuit a cell of EMF 1 . 5V gives balance point...

Given,

${E}_{1} = 1 . 5V$

${l}_{1} = 36cm$

${E}_{2} = 2 . 5v$

${l}_{2} = ?$

AS we know,

$\dfrac{{E}_{1}}{{E}_{2}} = \dfrac{{l}_{1}}{{l}_{2}}$

$\dfrac{1 \cdot 5}{2 \cdot 5} = \dfrac{36}{{l}_{2}}$

$\dfrac{3}{5} = \dfrac{36}{{l}_{2}}$

${l}_{2} = 60cm$