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NEET 2020
Exam
NEET
Year
2020
Subject
Physics
Chapter
Current Electricity

NEET 2020 · Physics · Current Electricity

For the circuit shown in the figure, the current I will be

For the circuit shown in the figure, the current II will be For the circuit shown in the figure, the current I will be

Options

  1. A0.75A0 . 75A
  2. B1A1A
  3. C1.5A1 . 5A
  4. D0.5A0 . 5A

Correct answer

B. 1A1A

Step-by-step solution

In the above circuit the cells are connected with opposite polarity it means the net EMF is, E=E1+E2=(2+4)V=6VE = {E}_{1} + {E}_{2} = \left(2 + 4\right)V = 6V and, all the resistance is connected in series, R=R1+R2+R3R = {R}_{1} + {R}_{2} + {R}_{3} ⇒I=2+44+1+1=66=1A⇒ I = \dfrac{2 + 4}{4 + 1 + 1} = \dfrac{6}{6} = 1A.
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