NEET2020PhysicsCurrent ElectricityActual
For the circuit shown in the figure, the current I will be
Options
- A0 . 75   A
- B1   A
- C1 . 5   A
- D0 . 5   A
Correct answer
B. 1   A
Step-by-step solution
In the above circuit the cells are connected with opposite polarity it means the net EMF is, E = E 1 + E 2 = 2 + 4   V = 6   V and, all the resistance is connected in series, R = R 1 + R 2 + R 3 ⇒ I = 2 + 4 4 + 1 + 1 = 6 6 = 1   A .