A charged particle having drift velocity of 7.5 × 10 ^ - 4 m s ^ - 1 in an electric field of 3 × 10 ^ - 10 V m ^ - 1 , has a mobility in m ^ 2 V ^ – 1 s ^ – 1 of:

Correct answer: A. 2.5 × 10 ^ 6 Drift velocity is given by, v _ d = E × μ ⇒ μ = v _ d E = 7 .5 × 10 ^ - 4 3 × 10 ^ - 10 μ = 2.5 × 10 ^ 6 m ^ 2 V ^ - 1 s ^ - 1

NEET 2020

Exam: NEET
Year: 2020
Subject: Physics
Chapter: Current Electricity

NEET 2020 · Physics · Current Electricity

A charged particle having drift velocity of 7.5 × 10 ^ - 4 m s ^ -...

A charged particle having drift velocity of

7.5 \times {10}^{- 4}m{s}^{- 1}

in an electric field of

3 \times {10}^{- 10}V{m}^{- 1}

, has a mobility in

{m}^{2}{V}^{– 1}{s}^{– 1}

of:

Options

A $2.5 \times {10}^{6}$
B $2.5 \times {10}^{– 6}$
C $2.25 \times {10}^{– 15}$
D $2.25 \times {10}^{15}$

Correct answer

A. $2.5 \times {10}^{6}$

Step-by-step solution

Drift velocity is given by, ${v}_{d} = E \times \mu$

$⇒ \mu = \dfrac{{v}_{d}}{E} = \dfrac{7 .5 \times {10}^{- 4}}{3 \times {10}^{- 10}}$

$\mu = 2.5 \times {10}^{6}{m}^{2}{V}^{- 1}{s}^{- 1}$

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